Readable function pointers

Consider the following declaration


It’s artificial (generated with the ever-helpful geordi bot), although I’m sure that if you looked hard enough, a similar one would appear somewhere in the wild. In the above case, foo is a pointer to function taking pointer to function taking char* and char* and returning int returning pointer to array of char*. I think that even seasoned C and C++ programmers will agree that this is quite confusing at first glance. Or second. And third. Especially for people less versed in “C gibberish”, as aptly calls it.

Checking whether a class has a member function with a given signature

When writing template code, being able to detect whether a type has a method with a given signature may be very useful. For example, when writing a custom buffer, checking for T::size() may allow us to preallocate memory in an input function. Checking for T::operator bool() will tell us whether our type is testable without writing specializations for every such type, which would be especially tedious for unnamed types. (side note: lambdas don’t have operator bool(), but they’re implicitly convertible to function pointers when their capture list is empty, which should make them testable, but they aren’t in VC 10 and 11)

Achieving the desired result requires basic understanding of SFINAE and overload resolution. Let’s say we want to check for existence of ::size() as used in the standard library or in the codebase of Qt, that is size_t (T::*)() const and int (T::*)() const respectively.

Right angle brackets and backwards compatibility

Ever since introduction of C++03 the standard committee set out to fix many minor annoyances in the language (auto, ranged for and initializer lists to name a few). Most of those are new things that cannot change the behaviour of existing code, but there are, of course, exceptions. In C++03 the first line of the following code was ill-formed, because >> was parsed as operator>>.

std::vector<std::vector<int>>  X; // ill-formed
std::vector<std::vector<int> > Y; // ok